If α and β are the roots of the quadratic equation 2 x2+6x-5=0 , then find (α+β) and (α×β). ( 1 mark)
Comparing 2 x2+6x-5=0 with ax2+bx+c=0
We get, a=2, b=6, c=-5
Now, α+β= - b/a
⇒α+β= - 6/2 = -3
And (α×β)= c/a
⇒(α×β)= (-5)/2