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Question

If A and B are the sums of odd and even terms respectively in the expansion of (x+a)n, then (x+a)2n−(x−a)2n is equal to


A

4(A+B)

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B

4(A-B)

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C

AB

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D

4AB

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Solution

The correct option is D

4AB


If A and B denote respectively the sums of odd terms and even terms in the expansion (x+a)n

Then, (x+a)n=A+B....(1)

(xa)n=AB.....(2)

Squaring and subtracting equation (2)from (1) we get

(x+a)2n(xa2n)=(A+B)2(AB)2

(x+a)2n(xa)2n=4AB


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