If a and b are the two vectors such that |a|=3√3,|b|=4 and |a+b|=√7, then the angle between a and b is
A
120o
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B
60o
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C
30o
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D
150o
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Solution
The correct option is D150o Given that, |a|=3√3,|b|=4 and |a+b|=√7 Now, |a+b|2=|a|2+|b|2+2|a||b|cosθ ⇒(√7)2=(3√3)2+42+2(3√3)(4)cosθ ⇒7=27+16+24√3cosθ ⇒24√3cosθ=−36 ⇒cosθ=−32√3=−√32 ⇒θ=150o