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Question

If A and B are two events associated with a random experiment such that P(AB)=0.8,P(AB)=0.3 and P(¯¯¯¯A)=0.5, find P(B).

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Solution

We know,

P(AB)=0.8

P(AB)=0.3

P(¯¯¯¯A)+P(A)=0.5

P(A)=10.5=0.5

Now, by addition theorem on probability

P(AB)=P(A)+P(B)P(AB)

0.8 = 0.5+ P(B) - 0.3

0.8 = P(B) + 0.2

P(B) = 0.8 -0.2 = 0.6

P(B)=0.6


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