If A and B are two events associated with a random experiment such that P(A∪B)=0.8,P(A∩B)=0.3 and P(¯¯¯¯A)=0.5, find P(B).
We know,
P(A∪B)=0.8
P(A∩B)=0.3
⇒P(¯¯¯¯A)+P(A)=0.5
⇒P(A)=1−0.5=0.5
Now, by addition theorem on probability
P(A∪B)=P(A)+P(B)−P(A∩B)
0.8 = 0.5+ P(B) - 0.3
0.8 = P(B) + 0.2
P(B) = 0.8 -0.2 = 0.6
∴P(B)=0.6