Given, A⊂B then . A∩B=A.
Thus, P( A∩B )=P( A )
Now, probability if both A and B event happens,
P( A|B )= P( A∩B ) P( B ) P( B )= P( A∩B ) P( A|B ) P( B )= P( A ) P( A|B ) [ P( A∩B )=P( A ) ]
Also,
0<P( B )≤1 0< P( A ) P( A|B ) ≤1 0×P( A|B )<P( A )≤1×P( A|B ) 0<P( A )≤P( A|B )
Therefore,
P( A|B )≥P( A )
Hence, option (C) is correct.
If A and B are two events such that A⊂ B and P(B) ≠ 0, then which of the following is correct?
(a) P(AB)=P(A)P(B) (b) P(AB)<P(A) (c) P(AB)≥P(A) (d) None of these
If A and B are two events such that A ⊂ B and P (B) ≠ 0, then which of the following is correct?
A.
B.
C.
D. None of these