The probability of A is 1 4 the probability of B is 1 2 and P( A∩B )= 1 8 .
Use the formula for the value of probability for not A and not B as,
P=1−P( A∪B ) =1−[ P( A )+P( B )−P( A∩B ) ]
Here, P is of probability for not A and not B.
Substitute the given values in the above formula we get,
P=1−[ 1 4 + 1 2 − 1 8 ] =1− 5 8 = 3 8
Thus, the value of probability for not A and not B is 3 8 .
IF A and B are two events such that P(A)=14,P(B)=12 and P(A∩B)=18 Find P (not A and not B)
If A and B are two events such that, find P (not A and not B).