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Mutually Exclusive Events

If A and B ar...

Question

If A and B are two events, the probability of occurrence of either A or B is given as _______.

P(A) + P(B)

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P (A \cup B)

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P(A)P(B)

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P(AB)

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Solution

The correct option is B $P (A \cup B)$
If A and B are two events, then A union B refers to the occurrence of either A or B or both which means all the elements of the two events have equal likely chances to occur in an event known as A union B.

Suggest Corrections

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A

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P (A \cup B) = P (A) + P (B) - P (A \cap B)

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P (A \cup B \cup C) = P (A) + P (B) - P (A \cap B) - P (B \cap C) - P (A \cap C) + P (A \cap B \cap C)

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P (A \cup B) = P (A) + P (B) - P (A \cap B)

P (A \cup B \cup C) = P (A) + P (B) + P (C) - P (A \cap B) - P (B \cap C) - P (A \cap C) + P (A \cap B \cap C)

P (E)

E .

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B

∣ ∣ ∣ ∣ ∣ \begin{matrix} P (A) - 1 & P (B) & - P (A \cap B) P (B) & - P (A \cap B) & P (A) - 1 - P (A \cap B) & P (A) - 1 & P (B) \end{matrix} ∣ ∣ ∣ ∣ ∣ = 0,

P (A \cup B) = P (A) + P (B) - P (A \cap B)

P (A \cup B \cup C) = P (A) + P (B) + P (C) - P (A \cap B) - P (B \cap C) - P (A \cap C) + P (A \cap B \cap C)

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