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Question

If A and B are two events, then P (A ∩ B) =
(a) P A P B
(b) 1 − P (A) − P (B)
(c) P (A) + P (B) − P (A ∩ B)
(d) P (B) − P (A ∩ B)

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Solution

(d) P (B) − P (A ∩ B)



From the diagram, we get AB and A¯ B are mutually exclusive events such that (AB) (A¯B)=B. Therefore by addition theorem of probability we have P(AB) + P(A¯B) = P(B) PAB=PB-PAB

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