If A and B are two fixed points on the circumference of the circle such that line joining A and B passes through the centre of that circle, then the locus of the point P such that the $∠ A P B = 90^{\circ}$ is ___ of the circle.

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Solution

Since line joining points A and B passes through the centre of the circle, so AB is the diameter of the circle,
Also, we know that angle in a semi-circle is $90^{\circ}$ , so the point P is the point on the circumference of the cirle.

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If A and B are two fixed points on the circumference of the circle such that line joining A and B passes through the centre of that circle, then the locus of the point P such that the ∠APB=90∘ is ___ of the circle.

Since line joining points A and B passes through the centre of the circle, so AB is the diameter of the circle, Also, we know that angle in a semi-circle is 90∘, so the point P is the point on the circumference of the cirle.

If A and B are two fixed points on the circumference of the circle such that line joining A and B passes through the centre of that circle, then the locus of the point P such that the $∠ A P B = 90^{\circ}$ is ___ of the circle.

Since line joining points A and B passes through the centre of the circle, so AB is the diameter of the circle,
Also, we know that angle in a semi-circle is $90^{\circ}$ , so the point P is the point on the circumference of the cirle.