The correct option is A A circle
Let A(x1,y1) and B(x2,y2) be two fixed points and P(h,k) be a variable point such that
∠APB=π2
Then, slope of AP× slope of BP=−1
⇒k−y1h−x1×k−y2h−x2=−1
⇒(h−x1)(h−x2)+(k−y1)(k−y2)=0
Hence, locus of (h,k) is
(x−x1)(x−x2)+(y−y1)(y−y2)=0
which is a circle having AB as diameter.