If $a a n d b$ are two integers then following may not be an integer.

$a + b$

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$a - b$

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$a \times b$

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$a \div b$

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Solution

The correct option is D
$a \div b$

Let us suppose $a a n d b$ two integers as $2 a n d 3$
Now, For $a + b$ = $2 + 3 = 5$ is an integer.
For, $a - b = 2 - 3 = - 1$ is an integer.
For, $a \times b = 2 \times 3 = 6$ is an integer.
And for $a \div b = 2 \div 3 = 0.666666 . .$ is not an Integer.
Hence, (D) is the correct option

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Similar questions

If $a$ and $b$ are two integers, then which of the following may not be an integer?

If a and b are two integers, then which of the following may not be an integer?

(a) $a + b$
(b) $a - b$
(c) $a \times b$
(d) $a \div b$

Question 24

If a and b are two integers, then which of the following may not be an integer?

(a) $a + b$
(b) $a - b$
(c) $a \times b$
(d) $a \div b$

Write the converse of the following statement : ' If two integers a and b are such that a > b, then a - b is always a positive integer'.

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