If A and B are two matrices such that AB=A and BA=B, then
A
(A3−B3)5=(A5−B5)3
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B
(A4−B4)3=A12−B12
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C
(A−B) is idempotent
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D
(A10−B10) is nilpotent
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Solution
The correct options are A(A3−B3)5=(A5−B5)3 D(A10−B10) is nilpotent AB=A⇒ABA=A2⇒A2=A Similarly B2=B A and B are idempotent Also (A−B)2=(A−B)(A−B) =A2−AB−BA+B2=A−A−B+B=0 (A−B) is nilpotent