If A and B are two matrices such that AB=B and BA=A, then
A is nilpotent
A+B is idempotent
A−B is idempotent
A−B is nilpotent
Given : AB=B and BA=A
⇒BAB=B2
⇒(BA)B=B2
⇒AB=B2
⇒B=B2
Hence, B is idempotent and similarly is A
(A–B)2=A2–AB–BA+B2
=A–B–A+B=0
⇒A–B is nilpotent.