If A and B are two mutually exclusive events such that $P (A) = 0.55$ and $P (B) = 0.35$ then $P (¯ A \cup ¯ B) =$

\frac{1}{4}

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\frac{1}{2}

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\frac{1}{8}

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Solution

The correct option is D 1
Doesn't matter what is the value of $P (A)$ or $P (B)$ .
Because A & B both are mutually cases.
So $P (¯ A \cup ¯ B) = 1$ .

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Similar questions

= 0.3 a n d P (B) = 0.6,

p (¯ A \cap ¯ B) = 0.28

P (A \cap B) = 0

P (B) \neq 1

P (A ∣ ¯ B) =

P (A) > 0

P (B) \neq 1

P (¯ A / ¯ B) =

P (A) = \frac{3}{5}

P (B) = \frac{1}{5}

P (A \cup B)

P (A) = \frac{1}{4}

P (B) = \frac{1}{6}

P (C) = \frac{2}{3}

P (A \cup B \cup C) = P (A) + P (B) + P (C)

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