Question

If $aandb$ are two negative integers such that $a>b$,then $a-b$is always ___________________

Answer 1

It is given that $aandb$are negative integers such that $a>b$

$$\begin{gathered} a=-3andb=-4 \\ suchthat-3>-4 \end{gathered}$$

Now

$a-b=(-3)-(-4)$

$$\begin{gathered} =-3+4 \\ =1 \end{gathered}$$

Therefore we conclude that if $aandb$are negative integers such that $a>b$,then $a-b$is always a positive integer