If A and B are two non-zero square matrices of the same order such that the product AB=0, then
A
both A and B must be singular
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B
exactly one of them must be singular
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C
atleast one of them must be non-singular
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D
none of these
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Solution
The correct option is B both A and B must be singular Assume that A is non-singular, then A−1 exists. Thus AB=0⇒A−1(AB)=(A−1A)B=0 ⇒IB=0 ∴B=0. A contradiction. ⇒ A is singular, similarly B is also singular. Hence, both A and B must be singular.