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Question

If a and b are two odd positive integers such that a>b, then prove that one of the two numbers a+b2 and ab2 is odd and the other is even.

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Solution

Since a and b are odd numbers , we can write a=2n+1 and b=2n+1

So a+b2= n+n+1 and ab2= nn"

If n+n is odd then nn must also be odd and If n+n is even then nn must also be even .

Thus we can also say that If n+n+1 is odd then nn must be even and
If n+n+1 is even then nn must be odd .

So it is proved that one of a+b2 and ab2 is odd and other is even

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