If A and B are two points on a circle such that m $(¯ A B) = 260^{o}$ . A possible value for the angle subtended by are BA at a point on the circle is

$100^{o}$

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$75^{o}$

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$50^{o}$

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$25^{o}$

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Solution

The correct option is C
$50^{o}$

A and B are two points on the circle such that reflex $∠ A O B = 260^{o}$

$∴ ∠ A O B = 360^{o} - 260^{o} = 100^{o}$

C is a point on the circle

$∴$ By joining AC and BC,

$∠ A C B = \frac{1}{2} ∠ A O B = \frac{1}{2} \times 100^{o} = 50^{o}$

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If A and B are two points on a circle such that m(¯AB)=260o. A possible value for the angle subtended by are BA at a point on the circle is

The correct option is C 50o A and B are two points on the circle such that reflex ∠AOB=260o ∴∠AOB=360o−260o=100o C is a point on the circle ∴ By joining AC and BC, ∠ACB=12∠AOB=12×100o=50o

If A and B are two points on a circle such that m $(¯ A B) = 260^{o}$ . A possible value for the angle subtended by are BA at a point on the circle is

The correct option is C
$50^{o}$

A and B are two points on the circle such that reflex $∠ A O B = 260^{o}$

$∴ ∠ A O B = 360^{o} - 260^{o} = 100^{o}$

C is a point on the circle

$∴$ By joining AC and BC,

$∠ A C B = \frac{1}{2} ∠ A O B = \frac{1}{2} \times 100^{o} = 50^{o}$