Question

If $A$ and $B$ are two points on the circle $x^2+y^2-4x+6y-3=0$ which are farthest and nearest respectively from the point $(7,2)$ then

• A. $A=(2-2\sqrt{2},-3-2\sqrt{2})$
• B. $A=(2+2\sqrt{2},-3+2\sqrt{2})$
• C. $B=(2+2\sqrt{2},-3+2\sqrt{2})$
• D. $B=(2-2\sqrt{2},-3+2\sqrt{2})$

Answer 1

Answer: (A), (C)

The correct options are
A $A=(2-2\sqrt{2},-3-2\sqrt{2})$
C $B=(2+2\sqrt{2},-3+2\sqrt{2})$