If A and B are two sets such that n (A) = 20, n(B) = 25 and $n (A \cup B)$ = 40, then write $n (A \cap B)$ .

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Solution

$n (A \cup B) = n (A) + n (B) - n (A \cap B)$

$n (A \cap B) = n (A) + n (B) - n (A \cap B)$

= 20+25-40

= 5

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