If a and b are two unequal positive numbers, the:

\frac{2 a b}{a + b} > \sqrt{a b} > \frac{a + b}{2}

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\sqrt{a b} > \frac{2 a b}{a + b} > \frac{a + b}{2}

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\frac{2 a b}{a + b} > \frac{a + b}{2} > \sqrt{a b}

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\frac{a + b}{2} > \frac{2 a b}{a + b} > \sqrt{a b}

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\frac{a + b}{2} > \sqrt{a b} > \frac{2 a b}{a + b}

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Solution

The correct option is E $\frac{a + b}{2} > \sqrt{a b} > \frac{2 a b}{a + b}$
a and b are two unequal positive numbers.
$∴ A . M > G . M > H . M \frac{a + b}{2} > \sqrt{a b} > \frac{2 a b}{a + b}$

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