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Phase Difference

If a and b is...

Question

If a and b is height of two antennas then maximum distance upto which they can be placed apart is $\sqrt{p a R} + \sqrt{q b R}$ . (R is radius of earth)
Find value of p+q

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Solution

R=Radius of Earth $h_{t}$ =a
$d_{m}$ =Maximum distance they can be placed apart $h_{R}$ =b

$d_{m} = \sqrt{2 R h_{T} + {2 R h}_{R}}$

from the question $\sqrt{p a R} + \sqrt{q b R}$
$p + q = 2 + 2$
$= 4$

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