If a and ℓ be the first and last term of an A.P.and S be the sum of its all terms, then its common difference is.
A
ℓ2+a22S−ℓ−a
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B
ℓ2−a22S−ℓ−a
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C
ℓ2−a22S+ℓ+a
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D
none of these
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Solution
The correct option is Bℓ2−a22S−ℓ−a Let the terms of A.P. are a,a+d,a+2d,...a+(n−1)d Given S=n2(a+l)∴n=2Sa+l Again l=a+(n−1)d ∴l=a+(2Sa+l−1)d ∴d=(l−a)(l+a)2S−1−a d=l2−a22S−l−a Hence, option 'B' is correct.