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Question

If a:b=1:5, then the roots of the equation ax2bx+4a=0 is/are

A
4
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B
1
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C
1
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D
5
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Solution

The correct option is B 1
Given equation ax2bx+4a=0
Now, we know that
a:b=1:5ab=15b=5a

The sum of coefficients
=ab+4a=a5a+4a=0
So, one root is 1
Now, let the other root be α
Product of roots
α×1=4aaα=4

Hence, the roots are 1,4

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