If a-b-1-6- a-0- b-0 then the roots of the equation ax2-bx-5a-0 is-are

A:b=1:6 ⇒ b=6a nbsp; ax^2+bx+5a=0 ⇒ a b+5a=0 We know that for a quadratic equation ax^2+bx+c=0, a,b,c∈ℝ if a b+c=0, then roots are 1 and ca Hence, roots o ...

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Standard XIII

Mathematics

Roots under Different Values of Coefficients

If a:b=1:6, a...

Question

If $a : b = 1 : 6, a \neq 0, b \neq 0$ then the roots of the equation $a x^{2} + b x + 5 a = 0$ is/are

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Solution

The correct option is C $- 5$
$a : b = 1 : 6$
$\Rightarrow b = 6 a$
$a x^{2} + b x + 5 a = 0$
$\Rightarrow a - b + 5 a = 0$

We know that for a quadratic equation $a x^{2} + b x + c = 0, a, b, c \in R$ if $a - b + c = 0,$ then roots are $- 1$ and $- \frac{c}{a}$
Hence, roots of the required equation are $- 1$ and $- 5.$

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Roots under Different Values of Coefficients

Standard XIII Mathematics

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If a:b=1:6, a≠0, b≠0 then the roots of the equation ax2+bx+5a=0 is/are

The correct option is C −5 a:b=1:6 ⇒b=6a ax2+bx+5a=0 ⇒a−b+5a=0 We know that for a quadratic equation ax2+bx+c=0, a,b,c∈R if a−b+c=0, then roots are −1 and −ca Hence, roots of the required equation are −1 and −5.

If $a : b = 1 : 6, a \neq 0, b \neq 0$ then the roots of the equation $a x^{2} + b x + 5 a = 0$ is/are