If $a + b = 10$ and $a b = 24$ , then what is the value of $a^{3} + b^{3}$

280

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152

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140

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72

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Solution

The correct option is A $280$
${(a + b)}^{3} = a^{3} + b^{3} + 3 a b (a + b)$
$1000 = a^{3} + b^{3} + 720$
$a^{3} + b^{3} = 280$

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Similar questions

a + b = 10

a b = 2

a^{3} + b^{3}

a^{3} + b^{3} + c^{3} - 3 a b c ?

If $a + b + c = 0$ , then the value of $(a + b - c)^{3} + (b + c - a)^{3} + (c + a - b)^{3}$ is:

a^{3} + b^{3} =

a + b + c = 5

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