Question

If a:b = 2:5 and x:y = 9:15
then the value of $\frac{5ay-2bx}{7bx-3ay}$

• A. 1:1
• B. 5/11
• C. None of the above
• D. 11/5

Answer 1

The correct option is D

11/5

$\frac{5ay-2bx}{7bx-3ay}=\frac{[5\left(\frac{ay}{bx}\right)-2]bx}{[7-3\left(\frac{ay}{bx}\right)]bx}=\frac{5\frac{a}{b}\times \frac{y}{x}-2}{7-3(\frac{a}{b}\times \frac{y}{x})}=\frac{5(\frac{2}{5}\times \frac{15}{4})-2}{7-3\left(\frac{3}{2}\right)}=\frac{\frac{15}{2}-2}{7-\frac{9}{2}}=\frac{15-4}{14-9}=\frac{11}{5}$