If a - b - 2- a - - b - 2-144 and a -4- find b -

We #160;know #160;a #8594; #215;b #8594;2+a #8594;. #160;b #8594;2=a #8594;2 #160;b #8594;2 #8658;144=42 #160;b #8594;2 #8658;144= ...

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Question

If ${|\vec{a} \times \vec{b}|}^{2} + {(\vec{a} . \vec{b})}^{2} = 144$ and $|\vec{a}| = 4,$ find $|\vec{b}|$ .

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If {|\vec{a} \times \vec{b}|}^{2} + {|\vec{a} \cdot \vec{b}|}^{2} = 144 and |\vec{a}| = 4, then |\vec{b}|

| \to a \times \to b |^{2} + (\to a \cdot \to b)^{2} = 144

| \to a | = 4

| \to b | =

If | \to a \times \to b |^{2} + | \to a \cdot \to b |^{2} = 144

| \to a | = 4

| \to b |

(¯ ¯ ¯ a \times ¯ ¯ b)^{2} + (¯ ¯ ¯ a \cdot ¯ ¯ b)^{2} = 144

| a | = 4

| b |

Given $A = 2 (a + b) h$ find $a$ if $A = 144, b = 1, h = 12$

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