If a−b=2, and aa+bb=cc0 then find the value of a−b−2c.
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Solution
These problems involve basic number (i) aa+bb=11(a+b)
(ii) aa,bb are two-digit numbers Hence their sum cannot exceed 198 So c must be 1 (iii) Hence cc0=110 This implies a+b=10 or a=6 and b=4 Such problems are part of a category of problems called alphanumerics