If A+B=2C and C+D=2A, then
If A+B⇌C+D; KC=K1 and E⊖=aV; 2A+2B⇌2C+2D; KC=K2 and E⊖=bV then:
Add 2a+3b+c+d, −a+b−c−d and 3a−4b−2c−2d. [3 MARKS]