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Question

If a:b=3:1 and b:c=5:1 then find the value of (a315b2c)3.

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Solution

Given
bc=51
b=5c
and
ab=31
a=3b=3×5c=15c
Now,
(a315b2c)3=((15c)315(5c)2c)3
=(153c315×52×c3)3
=(15315×52)3
=(15×155×5)3
=(3×3)3
=93
=729

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