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Question

If a:b=3:1 nd b:c=5:1 then find the value of

A
(a315b2c)3
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B
a27bc
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C
both a and b
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D
none of this
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Solution

The correct option is B a27bc
Given that,
a:b=3:1 and b:c=5:1

a:b=15:5 and b:c=5:1

a:b:c=15:5:1

Let, a=15k then b=5k,c=k

(i)(a315b2c)3=(15k×15k×15k15×5k×5k×k)3=(3×3)3=93=729

(ii)a27bc=15k×15k7×5k×k=15×37=457

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