If a:b= $3$ : $5$ , find
$(10 a + 3 b) : (5 a + 2 b)$

9 : 8

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3 : 5

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9 : 5

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7 : 5

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Solution

The correct option is C $9 : 5$
Given $a : b = 3 : 5$ , Let $a = 3 k$ and $b = 5 k$

Then, $(10 a + 3 b) : (5 a + 2 b)$

$= \frac{10 \times 3 k + 3 \times 5 k}{5 \times 3 k + 2 \times 5 k}$

$= \frac{30 k + 15 k}{15 k + 10 k}$

$= \frac{45 k}{25 k}$

$= \frac{9}{5}$

$(10 a + 3 b) : (5 a + 2 b) = 9 : 5$

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Similar questions

a : b = 3 : 5

(10 a + 3 b) : (5 a + 2 b)

a : b = \frac{2}{9} : \frac{1}{3}, b : c = \frac{2}{7} : \frac{5}{14}, d : c = \frac{7}{10} : \frac{3}{5},

a : b : c : d

A : B = 3 : 4,

B : C = 5 : 7

C : D = 8 : 9,

A : B

Fill in the blanks:

$(i) - 4 \times \frac{7}{9} = \frac{7}{9} \times$ ___

$(i i) \frac{5}{11} \times \frac{- 3}{8} = \frac{- 3}{8} \times$ ___

$(i i i) \frac{1}{2} \times (\frac{3}{4} + \frac{- 5}{12}) = \frac{1}{2} \times$ ____ $+ (\times) \frac{- 5}{12}$

$(i v) \frac{- 4}{5} \times \frac{5}{7} \times$ ___ $= (\frac{- 4}{5} \times \frac{5}{7}) \times \frac{- 8}{9}$

If A:B = $\frac{1}{2} : \frac{3}{8}$ , B:C = $\frac{1}{3} : \frac{5}{9}$ and C:D = $\frac{5}{6} : \frac{3}{4}$ , then the ratio A:B:C:D is

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