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Question

If (ab)=3 and ab=28, then the value of (a+b) is equal to.

A
±21
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B
±15
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C
±17
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D
±11
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Solution

The correct option is D ±11
Given (ab)=3 and ab=28

Using identities we know that,
(a+b)2(ab)2=4ab
(a+b)2=(ab)2+4ab
(a+b)2=32+4(28)
(a+b)2=9+112
(a+b)2=121
(a+b)2=112
(a+b)=±11

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