If A $+$ B $= 45^{o}$ , then find the value of $sin A cos B + cos A sin B$ .

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Solution

$s i n (A) c o s (B) + c o s (A) s i n (B)$

$= s i n (A + B)$

$= s i n (45^{\circ})$

$= \frac{1}{\sqrt{2}}$

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