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Question

If (a+b)=6, and ab=2, then the value of 1a2+1b2 is equal to


A

8

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B

12

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C

16

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D

4

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Solution

The correct option is A

8


Given (a+b)=6

Squaring both sides we get

(a+b)2=36

a2+b2+2ab=36

a2+b2+2×2=36 (as ab=2)

a2+b2=364

a2+b2=32 . . . (1)

The given expression is

1a2+1b2

=a2+b2a2b2

=(a+b)22aba2b2

=(6)22×(2)(2)2

=3644

=8


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