Question

If $A+B={90}^o$, then ......

• A. $\sin A=\sin B$
• B. $\cos A=\cos B$
• C. $\tan A=\tan B$
• D. $\sec A=\text{cosec}B$

Answer 1

The correct option is D $\sec A=\text{cosec}B$

$\sec A=\frac{r}{x}$ and $\text{cosec}A=\frac{r}{x}$

So, $\sec A=\text{cosec}A$