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Question

If (ab),a and (a+b) are zeros of the polynomial 2x36x2+5x7, write the value of a.

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Solution

f(x)=2x36x2+5x7

Let α,β and γ be the zeroes.

Then, α=ab,β=aandγ=a+b

We know that if α,βandγare the zeroes of a cubic polynomial,

ax3+bx2+cx+d=0

then, α+β+γ=ba


(ab)+a+(a+b)=(6)2

3a=3

a=1

So, the value of a=1


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