If $(a − b),a$ and (a+b) are zeros of the polynomial 2x3−6x2+5x−7, write the value of $a$.
Given: (a−b), a and (a+b) are zeros of the polynomial 2x3−6x2+5x−7
By using the relationship between the zeroes of the cubic polynomial.
We have,
Sumofzeroes=−coefficientofx2coefficentofx3
⇒a−b+a+a+b=−(−6)2
⇒3a=3
⇒a=1
Hence, the value of a is 1