If $A > B$ and $C < 0$ , then which of the following is not true?

A C < B C

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A + C > B + C

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A - C < B - C

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All of the above

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Solution

The correct option is C $A - C < B - C$
If $A > B$ and $C < 0$ then multiplication of both sides by $C$ reverses the inequality. Which implies
$A C < B C$ . Also adding and subtracting in inequality, gives
$A + C > B + C$ and
$A - C > B - C$
But $A - C < B - C$ is not possible

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