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Question

If a, b and c are all non-zero and a + b + c = 0, then find the value of a2bc+b2ac+c2ab.
  1. 3

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Solution

The correct option is A 3
We know that, a3+b3+c33abc=(a+b+c)(a2+b2+c2abbcca)
=0(a2+b2+c2abbcca) [a+b+c=0, given]
=0
a3+b3+c3=3abc
On dividing both sides by abc; we get,
a3abc+b3abc+c3abc=3
a2bc+b2ac+c2ab=3

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