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Question

If a,b and c are distinct positive real numbers in AP, then the roots of the equation ax2+2bx+c=0 are


A

imaginary

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B

rational and equal

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C

rational and distinct

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D

irrational

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Solution

The correct option is C

rational and distinct


Explanation for the correct option:

Finding the roots of the equation:

Given that, a,b,c are in A.P, then

2b=a+c

Now, the given equation becomes:

ax2+(a+c)x+c=0

So, Discriminant D=b2–4ac

=(a+c)2-4ac=a2+c2+2ac-4ac=a2+c2-2ac=a-c2

Now, a-c2≥0

⇒ D≥0

∴The roots of the equation are rational and distinct.

Hence, option ‘C’ is Correct.


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