If A- B and C are interior angles of a triangle A B C- then sin B-C 2-a sin A 2b cos A 2c -sin A 2d -cos A 2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Range of Trigonometric Ratios from 0 to 90 Degrees

If A, B and C...

Question

If A, B and C are interior angles of a triangle ABC, then $\sin (\frac{B + C}{2}) =$

(a) $\sin \frac{A}{2}$
(b) $\cos \frac{A}{2}$
(c) $- \sin \frac{A}{2}$
(d) $- \cos \frac{A}{2}$

Open in App

Solution

Suggest Corrections

Similar questions

\tan (\frac{C + A}{2}) = \cot \frac{B}{2}

\sin (\frac{B + C}{2}) = \cos \frac{A}{2}

sin (\frac{B + C}{2}) =

sin (\frac{B + C}{2}) =

A, B

C

A B C

sin (\frac{B + C}{2}) = cos \frac{A}{2} .

A, B

C

A B C

sin (\frac{B + C}{2}) = cos \frac{A}{2}

Join BYJU'S Learning Program