If A,B and C are invertible matrices and BAC=I, the value of A is
A
CB
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B
C−1B−1
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C
B−1C−1
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D
A−1
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Solution
The correct option is CB−1C−1 Given that, BAC=I Pre-multiplying the given equation with B−1 B−1BAC=B−1 i.e.,AC=B−1 Post multiplying the above equation by C−1 ACC−1=B−1C−1 A=B−1C−1