wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If a,b and c are non zero real numbers such that ab=2(a+b)bc=3(b+c) and ca=4(c+a) then the value of 5a+7b+c is

A
18
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
72
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
108
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
120
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 72
Given that
ab2(a+b)1a+1b=12
bc=3(b+c)1b+1c=13
ca=4(c+a)1c+1a=14
(1c+1a)(1a+1b)=1312
1c1a=16
1c+1a+1c1a=1416
2c=112c=24
1a=14124a=245
1b=1214b=247
5a+7b+c=24+24+24
=72

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Remainder Theorem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon