If a, b and c are the side lengths of the triangle such that a+b+ca−b−c=54.The perimeter of the triangle will be:
a+b+ca−b−c=54
Using componendo and dividendo
(a+b+c)+(a−b−c)(a+b+c)−(a−b−c)=91
a=9(b+c)
Perimeter of the triangle = a+b+c
= a+19a
= 109a.