If A B and C are three angles of a triangles in a relation cosA+cosB+cosC=3/2 . Then prove that the triangle is equilateral

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∣ ∣ ∣ ∣ \begin{matrix} - 1 & c o s C & c o s B c o s C & - 1 & c o s A c o s B & c o s A & - 1 \end{matrix} ∣ ∣ ∣ ∣

Δ A B C,

A, B, C

A . P

cos A + 2 cos B + cos C = 2

Δ A B C

A, B, C

A . P

cos A + cos B + cos C = 2,

c o s A + c o s B + c o s C \leq 3 / 2.

cos A + cos B + cos C = \frac{3}{2}

If A, B, C are angles of a triangles, then cos A + cos B + cos C is equal to

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