Every Point on the Bisector of an Angle Is Equidistant from the Sides of the Angle.
If A, B and C...
Question
If A, B and C are three points on a line, and B lies between A and C, then AB+BC=AC.
A
True
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B
False
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Solution
The correct option is A True Let A, B, and C be three distinct points of a line, with the respective coordinates x, y, and z. If x < y < z, then A-B-C.
Proof, By the ruler postulate:
AB = |y-x|
BC = |z-y|
AC = |z-x|.
But y-x is positive because x < y; similarly, z-y and z-x are positive. So:
AB = y-x
BC = z-y
AC = z-x
Finally: AB + BC = (y - x) + (z - y) = z-x =AC. Since AB + BC = AC, A-B-C by the definition of between.If A, B and C are three points on a line, and B lies between A and C.