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Question

If A, B and C are three points on a line, and B lies between A and C, then AB+BC=AC.

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A
True
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B
False
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Solution

The correct option is A True
Let A, B, and C be three distinct points of a line, with the respective coordinates x, y, and z. If x < y < z, then A-B-C.

Proof, By the ruler postulate:
  • AB = |y-x|
  • BC = |z-y|
  • AC = |z-x|.
But y-x is positive because x < y; similarly, z-y and z-x are positive. So:
  • AB = y-x
  • BC = z-y
  • AC = z-x
Finally:
AB + BC = (y - x) + (z - y)
= z-x
=AC.
Since AB + BC = AC, A-B-C by the definition of between.If A, B and C are three points on a line, and B lies between A and C.


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