Question

If $A,B$ and $C$are three sets,$A–(B\cap C)$is equal to

• A. $(A–B)\cup (A–C)$
• B. $(A–B)\cap (A–C)$
• C. $(A–B)\cup C$
• D. $(A–B)\cap C$

Answer 1

The correct option is A

$(A–B)\cup (A–C)$

Find the value of $\mathbf{}\mathit{A}\mathbf{}\mathbf{–}\mathbf{}\mathbf{(}\mathit{B}\mathbf{}\mathbf{\cap }\mathbf{}\mathit{C}\mathbf{)}\mathbf{}$:

Given that $A,B$ and $C$are three sets.

According to De’Morgan’s Law

We have $A–(B\cap C)=(A-B)\cup (A-C)$

Hence, the correct option is A.