If A, B and C are three sets such that A∩B=A∩C and A∪B=A∪C, then
B=C
Given that A∪B=A∪C and A∩B=A∩C
⇒(A∪B)∩C=(A∪C)∩C
⇒(A∩C)∪(B∩C)=C [∵(A∪C)∩C=C]
⇒(A∩B)∪(B∩C)=C......(1)
Again A∪B=A∪C
(A∪B)∩B=(A∪C)∩B
B=(A∩B)∪(C∩B)
=(A∩B)∪(B∩C)......(2)
From (1) and (2) we get,
B=C